LeetCode 371: Sum of Two Integers

Difficulty: Medium Topics: Math, Bit Manipulation

Problem Description

Given two integers a and b, return the sum of the two integers without using the operators + and -.Example 1:

Input: a = 1, b = 2 Output: 3 Example 2:

Input: a = 2, b = 3 Output: 5Constraints:- -1000 <= a, b <= 1000

Examples

Example 1: Input: a = 1, b = 2 Output: 3

Example 2: Input: a = 2, b = 3 Output: 5

Constraints

**- -1000 <= a, b <= 1000

Editorial

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Approach

Based on the problem (Binary Tree Level Order Traversal), the standard approaches are:

  1. BFS (Breadth-First Search) with Queue

    • Use a queue to traverse level by level
    • For each level, process all nodes currently in the queue
    • Add children to the queue for the next level
  2. DFS (Depth-First Search) with Level Tracking

    • Use recursion with level parameter
    • Group nodes by their depth level

Implementation Notes

  • Time Complexity: O(n) where n is the number of nodes
  • Space Complexity: O(w) where w is the maximum width of the tree

Code Template

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
 
class Solution:
    def levelOrder(self, root: Optional[TreeNode]) -> List[List[int]]:
        if not root:
            return []
        
        result = []
        queue = [root]
        
        while queue:
            level_size = len(queue)
            level_values = []
            
            for _ in range(level_size):
                node = queue.pop(0)
                level_values.append(node.val)
                
                if node.left:
                    queue.append(node.left)
                if node.right:
                    queue.append(node.right)
            
            result.append(level_values)
        
        return result

Similar Questions

  • [Add Two Numbers] (Difficulty: Medium)

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